z^2+2(1+i)z+2=

Solution for z^2+2(1+i)z+2= equation:

Simplifying
z2 + 2(1 + i) * z + 2 = 0

Reorder the terms for easier multiplication:
z2 + 2z(1 + i) + 2 = 0
z2 + (1 * 2z + i * 2z) + 2 = 0

Reorder the terms:
z2 + (2iz + 2z) + 2 = 0
z2 + (2iz + 2z) + 2 = 0

Reorder the terms:
2 + 2iz + 2z + z2 = 0

Solving
2 + 2iz + 2z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + 2iz + 2z + -2 + z2 = 0 + -2

Reorder the terms:
2 + -2 + 2iz + 2z + z2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 2iz + 2z + z2 = 0 + -2
2iz + 2z + z2 = 0 + -2

Combine like terms: 0 + -2 = -2
2iz + 2z + z2 = -2

Add '-2z' to each side of the equation.
2iz + 2z + -2z + z2 = -2 + -2z

Combine like terms: 2z + -2z = 0
2iz + 0 + z2 = -2 + -2z
2iz + z2 = -2 + -2z

Add '-1z2' to each side of the equation.
2iz + z2 + -1z2 = -2 + -2z + -1z2

Combine like terms: z2 + -1z2 = 0
2iz + 0 = -2 + -2z + -1z2
2iz = -2 + -2z + -1z2

Divide each side by '2z'.
i = -1z-1 + -1 + -0.5z

Simplifying
i = -1z-1 + -1 + -0.5z

Reorder the terms:
i = -1 + -1z-1 + -0.5z